the perimeter of an isosceles triangle is 32cm. the ratio of the equal side to its base is 3:2. find the area of the triangle
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GIVEN,ratio 3:2
let3x,3x,2x be the sides
=sum of all sides = 32
=3x+3x+2x=32
=8x=32
=x=4
AREA OF triangle =[\sqrt{s(s-a)(s-b)(s-c)][/tex]
area=32root2
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