Math, asked by shreyashwadaje28, 10 months ago

the perimeter of an isosceles triangle is 32cm. the ratio of the equal side to its base 3:2. find the area of the triangle

Answers

Answered by studyscorer
0

Answer:

Area = 45.25

Step-by-step explanation:

The perimeter of an isoscles trinagle = 2 * equal side + the third side

The ratio is 3:2 so,

Let the equal side be 3x and the base be 2x

Enter the values

2(3x)+ 2x = 32

6x + 2x= 32

8x = 32

x = 32/8

x= 4

Therefore, the equal sides are = 3 * 4= 12 and the base = 2*4= 8

Now, let's find the height

Let the height be x

By pythagorus theorum

AC^2 = AB^2 + BC^2

12^2 = x^2 + 8^2

144-64= x^2

x= √80

Area of triangle = 1/2 * base* height = 1/2 * 8 * √80 = 45.25

The End

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