Question

The perimeter of an isosceles triangle is 32cm.The ratio of the equal side to it's base is 3:2.Find the area of the triangl​

Answer 1

2

Step-by-step explanation:

The perimeter of an isosceles △=32cm .

Given that the ratio of the equal side to its base is 3:2.

So the ratio of all three sides of the isosceles △=3:3:2

Sum of the ratios = 3+3+2=8Length of equal side = 3/8 ×32=3×4=12

Length of the base = 2/8 ×32=2×4=8

According to Heron's formula, Area of an isosceles △ with equal sides a & base b = 1/4 ×b× √(4a²−b² )

Area of the given isosceles triangle,where a=12 & b=8

= 1/4 ×8×√ (4×12²)−8²

=2× √(4×144)−64

= 2×√ 576−64

=2×16× √2

= 32√ 2

∴m=2

Answer 2

Answer:

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