Math, asked by johndave12, 2 months ago

The perimeter of an isosceles triangle is 38 cm and two sides of the triangle are whole numbers in the ratio 3:8. What is the length (in cm) of the shortest side?

Answers

Answered by Anonymous
55

Question :-

1)The perimeter of an isosceles triangle is 36 centimeters and two sides of the triangle are in the ratio 2:5. Wh at is the number of centimeters in the length of the longest side?

Answer:-

The sides must be in the ratio 2 : 5 : 5

So..each equal part must be 3 cm

So the number of cm in the longest side =

5 / 12 * 36 =

5 * (36/12) =

5 * 3 =

15 cm

The shortest side is (2/12) (36) = 6

So 15 + 15 + 6 = 36

EDit to correct a previous error....

⏩hopes its helps you

Answered by Eutuxia
2

Given :

  • Perimeter = 38 cm
  • Ratio of side = 3:8

To find :

  • the shortest side

Solution :

Perimeter = 38cm

✳ As it is an isosceles triangle, there will be only 2 lengths. One of them will be the length of the equal sides

⇒ Sides ratio = 3 : 8

✳ Let the length of the sides be 3x and 8x.

✳ But, we are not given, that 3x is the length of an equal side or 8x.

✳ But, we know that sum of the 2 sides is greater than the 3rd side.

Case (1)

Taking 3x as an equal side. So,

⇒ 3x + 3x = 6x

  • But, 6x is less than 8x.
  • Hence, 3x is not the length of the equal side.
  • Therefore, the length of the equal side is 8x. And the third side is 3x.

Perimeter = 38cm

3x + 8x + 8x = 38 cm

               19x = 38

                      = 38/19

                      = 2 cm

                   x = 2cm

So,

3x = 3 × 2 = 6 cm

8x = 8 × 2 = 16 cm

8x = 8 × 2 = 16 cm

  • Therefore, the shortest side of the isosceles triangle is 6 cm.
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