Question

the perimeter of an isosceles triangle is 40. cm the base is two third of the sum of equal sides. find the area of the triangle

Answer 1

let equal side's be x.
x+x+2/3(x+x)=40
x+x+4/3x=40
10/3x=40
x=12
equal side=12,base=16
s={12+12+16}/2=20
area=√{20*(20-12)*(20-12)*(20-16)}=32√5

Answer 2

Refer to the above attachment :)