Question

the perimeter of an Isosceles triangle is 42 cm and it's base is 1 1/2(one space one by two) times each of the equal sides. find the length of each of the triangle. (given √7=2.64.)can any moderator help me...
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Answer 1

Answer:

same sides measure 12 and base measures 18

Step-by-step explanation:

Assume equal sides as of length x and base as y

x + x + y = 42 (perimeter)

2x + y = 42

Now, base is 1 ½ that is 3/2 of equal side

so we can write 2x + y = 42 as

2x + (3/2(x)) = 42

multiple above by 2

4x + 3x = 84

7x = 84

x = 12

therefore y = 3/2(x)

= 3/2(12)

= 36/2

= 18

Answer 2

Given,

• perimeter = 42cm
• $\sf \: base = 1 \dfrac{1}{2} \: of \: equal \: sides$

Solution:-

Let the equal sides be x

$\sf \: base = 1 \dfrac{1}{2} \: of \: equal \: sides \\ = \sf1 \dfrac{1}{2} \: \times x = 1 \frac{1}{2}x$

Now,

perimeter= 2×equal sides + base

$\sf42cm = 2 \times x + 1 \frac{1}{2} x$

$\sf 42cm = 2x + \dfrac{3x}{2}$

$\sf42cm = \dfrac{4x + 3x}{2}$

$\sf42 cm\times 2 = 7x$

$\sf \: \dfrac{42cm \times 2}{7} = x$

$\sf \: \frac{\cancel{42cm} \times 2}{ \cancel{7 \: }} = x$

$\sf6cm \times 2 = x$

$\therefore \sf \: x = 12cm$

Correct Answer:-

• 12cm