Question

the perimeter of an isosceles triangle is 42 cm and its base is 3/2
times each of the equilateral sides find the length of each side of the triangle and area of the triangle and the height of the triangle​

Answer 1

Answer:

Step-by-step explanation:

we know what is menat by isosceles triangle

in which two sides are equal and one diff side

given diff side=3/2equal side

given perimeter=42

let equal side = x

x+x+3/2x=42

7x/2=42

x/2=6

x=12

diff side =3/2x

=18

equal sides=12

area=root s*s-a*s-b*s-c

root 21*9*9*15

160m^2

area=160

1/2 base*height=160

height=320/base

320/18=18