Math, asked by hsharman5631, 11 months ago

The perimeter of an isosceles triangle is 42 cm and its base is 1.5 times each of its equal sides find a) the length of each side of the triangle b) area of the triangle c)height of the triangle chapter: herons formula class 9

Answers

Answered by basavaraj5392
1

Let ‘x’ be the measure of each equal sides

∴ Base = 3/2x

∴ x + x + 3/2x = 42 b[ P=a + b + c = 42 cm]

7/2x = 42

x = 12 cm

∴ Sides are, a = x = 12 cm

b = x = 12 cm

c = x = 3/2(12) cm = 18 cm

s = 42/2 = 21 cm

By heron’s formula

Area of triangle = √s(s-a)(s-b)(s-c)

= √21(21-12)(21-12)(21-18)

= √21(9)(9)(3)

= 9√21(3)

= 9√7×3×3

= 9×3√7

= 27√7 cm²

area of triangle = 1/2×b×h

27√7 = 1/2×18×h

27√7 = 9×h

(27√7)/9 = h

3√7 cm = h

Therefore, the length of each side of the triangle are 12cm,12cm and 18cm

Area of the triangle is 27√7 cm²

Height of the triangle is 3√7 cm

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