Question

The perimeter of an isosceles triangle is 42 cm and its base is 1 times
each of the equal sides. Find (i) the length of each side of the triangle,
(ii) the area of the triangle, and (iii) the height of the triangle. (Given,
root 7 = 2.64.)​

Answer 1

Answer:

14,240,34.29

Explanation:

Given:

perimeter=42 cm

base = 1×equal sides

To find:

length of each side

area if traingle

height of traingle

Sol:

If base = 1×equal sides

base = equal sides

therefore,all the sides are equal

let the side be x

perimeter of a triangle is sum of it's sides

x+x+x=42

3x=42

x=14 cm

therefore,length of each side is 14 cm.

Area of isoscles triangle = product of 2 sides and sin of an angle

area = 14×14×sin(60°){it is 60° bcoz all the sides are equal}

area=240 cm

area=1/2×base×height

240=1/2×14×h

240/7=h

h=34.29 cm

therefore,height is 34.29 cm

Hope it is correct and helps you.