Question

the perimeter of an isosceles triangle is 42 cm and its base is ½ times each of the equal sides find the height of the triangle (√7=2.64)​

Answer 1

Answer:

71.28sq units

Step by step Explanation:

Answer

(i)

the length of each side of the triangle:

1  

2

1

 

x+x+x=42

2

3​  

x+x+x=42

2

7  

x=42

x=12cm

side=12cm

(iii)

the height of the triangle

base  

2

+height  

2

=hypotenuse  

2

⇒height  

2

=12  

2

−9  

2

=63

∴height=  

63  

=3  

7

cm

(ii)

Area of the triangle

Area=  

2

1  

base×height=

2

1  

×18×3  

7  

=71.28sq units

Answer 2

Step-by-step explanation:

perimeter of isosceles triangle=42cm

let the equal side =×cm

base=×/2cm

perimeter=×/2+×+×=42

5×/2=42

5×=84

×=84/5

equal side=84/5cm

base=1/2×84/5=42/5cm