Question

the perimeter of an isosceles triangle is 42 cm and its base is 1 ½ times each of the equal sides. Find the length of each side of the triangles (Given, √7 = 2.64) with full explaination..

It's urgent pls answer me correct...
❌ Don't spam ❌​

Answer 1

Question:-

• the perimeter of an isosceles triangle is 42 cm and its base is 1 ½ times each of the equal sides. Find the length of each side of the triangles (Given, √7 = 2.64).

Given:-

• Perimeter of isosceles triangle is 42 cm
• Base is 1½ times of each equal sides

To find:-

• Length of each sides if triangle

Solution:-

$\underline{ \boxed{ \mathfrak{ \blue{Perimeter \: of \: Isosceles \: triangle= sum \: of \: all \: sides}}}}$

$\longrightarrow \: 42 = a + a + \frac{3}{2} a \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ( \: base = 1 \frac{1}{2} \: of \: sides)$

$42 = \frac{7a}{2}$

$7a = 42 \times 2$

$7a = 84$

$a = \frac{84}{7} = 12 \: cm$

$base = \: 1\frac{1}{2} \: = \frac{3}{2}$

$\cancel{12 } \: \: ^{6} \times \frac{3}{ \cancel{2} }$

$base = 18 \: cm$

Therefore the length of sides of triangle is 12 cm,12 cm ,18 cm.

$\huge{ \underline{ \color{maroon}{ \mathfrak{Verification:-}}}}$

Perimeter = sum of all sides

$= 12 \: cm + 12 \: cm \: + 18 \: cm$

$= 42 \: cm$

$\boxed{ \underline{ \mathfrak{ \blue{Hence \: proved \: that \: the \: measures \: are \: correct \: ✅}}}}$