Question

the perimeter of an isosceles triangle is 42 cm .Its base is 2\3times the sum of equal sides . find the length of each side of the triangle​

Answer 1

Answer:

let each of the equal sides be x  

let the base by y  

y = (2/3)(2x) = 4x/3  

so x + x + (4/3)x = 42  

multipy by 3  

3x + 3x + 4x = 126  

10x = 126  

x = 12.6  

so the base = (4/3)(12.6) = 16.8  

use Pythagoras to find the height, h  

h^2 + 8.4^2 = 12.6^  

h^2 = 88.2  

h √88.2  

Area = (1/2)base x height  

= (1/2)(16.8)√88.2  

= appr. 78.888

Step-by-step explanation:

Answer 2

Step-by-step explanation:

let the equal sides length are X

then,

sum of equal side is 2X

so, the length of base is 2X×2/3=4X/3

we know that perimeter of triangle =sum of all side

42cm=2X+4X/3

42cm=10X/3

126cm=10X

so X=12.6cm

after length of base =12.6×4/3

=16.8cm

length of all side are 12.6cm,12.6cmand 16.8cm