the perimeter of an isosceles triangle is 42 cn and its base is 1 whole 1/2 times each of the equal sides find the length of each side of the triangle and the area of the triangle and find the height of the triangle take √7=2.64.
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Hey here is your answer.
"48" is the correct answer
option (2) is your answer
I think my answer capable to clear your confusion
"48" is the correct answer
option (2) is your answer
I think my answer capable to clear your confusion
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Kashmirjannat:
but the answer is 12,12 and 18 cm
Let the side of the isosceles triangle be x
GIVEN
3/2 x +x +x=42cm
3x/2 + 2x =42
(3x+4x)/2=42
3x+4x=84
7x=84
x=12cm
side=12cm base=18cm
The height(altitude) of an isos. trangle divides it into two rt trangles
in a rt.trangle, base²+heigrt²=hypotenuse²
thus, 9²+h²=12²
h=√12²-9²
=√144-81 =√63 =3√7cm
area =1/2 x base x hieght
=1/2 x 18 x3√7
27√7cm²
GIVEN
3/2 x +x +x=42cm
3x/2 + 2x =42
(3x+4x)/2=42
3x+4x=84
7x=84
x=12cm
side=12cm base=18cm
The height(altitude) of an isos. trangle divides it into two rt trangles
in a rt.trangle, base²+heigrt²=hypotenuse²
thus, 9²+h²=12²
h=√12²-9²
=√144-81 =√63 =3√7cm
area =1/2 x base x hieght
=1/2 x 18 x3√7
27√7cm²
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