the perimeter of an isosceles triangle is 42cm and it's base is 3/2 times each of the equal sides. find the length of each side of the triangle area of the triangle and the height of the triangle.
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let the length of its equal side be x cm
so length of its base = 3x/2 cm
perimetrer of triangle = sum of three sides
x+x+3x/2=42
7x/2=42
x=12cm , base =12*3/2=18cm
so length of equal side =12cm and base=18cm
height of triangle =√(12^2-9^2)=√144-81=√63=3√7
area of triangle =1/2*base*height=1/2*18*3√7=27√7cmsquare Answer
so length of its base = 3x/2 cm
perimetrer of triangle = sum of three sides
x+x+3x/2=42
7x/2=42
x=12cm , base =12*3/2=18cm
so length of equal side =12cm and base=18cm
height of triangle =√(12^2-9^2)=√144-81=√63=3√7
area of triangle =1/2*base*height=1/2*18*3√7=27√7cmsquare Answer
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