Question

The perimeter of an isosceles triangle is 43/4 cm. If one of the side measures 9/4 cm. find the third side.

Answer 1

$\large{\sf{\underline{\underline{Question}}}}$



The perimeter of an isosceles triangle is $\dfrac{43}{4}$ cm. If one of the side measures $\dfrac{9}{4}$ cm. find the third side.



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$\large{\sf{\underline {\underline {Answer}}}}$



$\large{\sf \dfrac{25}{4}}$



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$\huge \pink{ \mid \underline{ \overline{ \sf Brainly \: Solution : }} \mid}$



$\sf Let \: the \: third \: side \: be \: x. \\ \\ \because \sf x + \frac{9}{4} + \frac{9}{4} = \frac{4 3 }{4} \\ \\ \to \sf x + \frac{18}{4} = \frac{43}{4} \\ \\ \sf \to x = \frac{43}{4} - \frac{18}{4} \\ \\ \sf \to x = \frac{25}{4}$



$\huge \orange{ \boxed{ \boxed{ \sf{ \therefore x = \dfrac{25}{4}}}}}$



✔✔ Hence, it is solved ✅✅.



$\huge \blue{ \boxed{ \boxed{ \mathscr{THANKS}}}}$

Answer 2

Other side =43/4-[2×(17/6)]

=43/4–17/3

=(129–68)/12

= 61/12

= 5.08 cm. Answer