Question

The perimeter of an isosceles triangle is 43/4 cm. If one of the side measures 9/4 cm. find the third side.​

Answer 1

$\large{\sf{\underline{\underline{Question}}}}$

The perimeter of an isosceles triangle is $\dfrac{43}{4}$ cm. If one of the side measures $\dfrac{9}{4}$ cm. find the third side.

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$\large{\sf{\underline {\underline {Answer}}}}$

$\large{\sf \dfrac{25}{4}}$

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$\huge \pink{ \mid \underline{ \overline{ \sf Brainly \: Solution : }} \mid}$

$\sf Let \: the \: third \: side \: be \: x. \\ \\ \because \sf x + \frac{9}{4} + \frac{9}{4} = \frac{4 3 }{4} \\ \\ \to \sf x + \frac{18}{4} = \frac{43}{4} \\ \\ \sf \to x = \frac{43}{4} - \frac{18}{4} \\ \\ \sf \to x = \frac{25}{4}$

$\huge \orange{ \boxed{ \boxed{ \sf{ \therefore x = \dfrac{25}{4}}}}}$

✔✔ Hence, it is solved ✅✅.

$\huge \blue{ \boxed{ \boxed{ \mathscr{THANKS}}}}$

Answer 2

         

Let the length of the unequal side be 9/4 cm.

So that the other are equal sides.

∴ Length of each other side will be,

$(\frac{43}{4}-\frac{9}{4}) \div 2 \ = \ \frac{34}{4} \div 2 \ = \ \frac{34}{4} \times \frac{1}{2} \ = \ \frac{17}{4}$

AND,

Let the length of each equal side be 9/4 cm.

So there are two equal sides of length 9/4 cm.

∴ The third side will be,

$\frac{43}{4}-(\frac{9}{4} \times 2) \ = \ \frac{43}{4}-\frac{18}{4} \ = \ \frac{25}{4}$

Hope this helps. Plz mark it as the brainliest.

Thank you. :-))