the perimeter of an isosceles triangle is 43 CM the length of its its congruent side is 1 cm less than twice the length of its base find the length of each side of the triangle
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Let the length of the base of the triangle be 'x', according to the question, the length of the congruent sides will be equal to 2x-1. Then the equation that forms is 2x-1+2x-1+x=43. Solving the equation, we get x=9. Thus the length of the base is 9cm and the length of the congruent sides will be equal to 2x-1, that is 17.
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