Question

the perimeter of an isosceles triangle is 48cm and each of its equal side is 15cm. find its area.​

Answer 1

Answer:

Perimeter of the isosceles triangle = 48 cm.

Perimeter of the isosceles triangle = 48 cm.The equal sides are 15 cm.

Perimeter of the isosceles triangle = 48 cm.The equal sides are 15 cm.The third side = 18 cm.

Perimeter of the isosceles triangle = 48 cm.The equal sides are 15 cm.The third side = 18 cm.By Heron’s formula, Area of the triangle = [24*(24–15)*(24–15)*(24–18)]^0.5

Perimeter of the isosceles triangle = 48 cm.The equal sides are 15 cm.The third side = 18 cm.By Heron’s formula, Area of the triangle = [24*(24–15)*(24–15)*(24–18)]^0.5= [24*9*9*6]^0.5

Perimeter of the isosceles triangle = 48 cm.The equal sides are 15 cm.The third side = 18 cm.By Heron’s formula, Area of the triangle = [24*(24–15)*(24–15)*(24–18)]^0.5= [24*9*9*6]^0.5= 108 sq cm. Answer.

Answer 2

Answer:

108 $cm^{2}$

Step-by-step explanation:

Let the triangle be named ABC

Let AB and AC be the equal sides

Let the third(unequal) side be x

Now perimeter of a triangle = sum of the three sides

15 + 15 + x  = 48

x  = 48 - 30

x = 18 cm

By using Heron’s formula, area of triangle=  √s(s−a)(s-b)(s−c)

s = semi perimeter = Perimeter/2 = 48/2 = 24

a = 15

b = 15

c = 18

Substituting the values:

√24(24-15)(24-15)(24-18)

√24(9) X (9) X (6)

3 X 3 X √144

9 X 12

108 $cm^{2}$

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