Question

The perimeter of an isosceles triangle
is 6 11/20 cm if one of its equani sides is
1 2/5 cm find the third side ​

Answer 1

$perimeter \: of \: triangle = 6 \frac{11}{20} cm = \frac{131}{11} cm \\ length \: of \: equal \: sides = 1 \frac{2}{5} cm = \frac{7}{5} cm\\ let \: length \: of \: unequal \: side = x \: cm \\ according \: to \: question \: \\ 2 \times \frac{7}{5} + x = \frac{131}{11} \\ \frac{14}{5} + x = \frac{131}{11} \\ x = \frac{131}{11} - \frac{14}{5} \\ x = \frac{655 - 154}{55} \\ x = \frac{501}{55} \\ x = 9 \frac{6}{55} \\ so \: length \: of \: unequal \: side \: is \: 9 \frac{6}{55} cm.$

I hope it may help you

Answer 2

Answer:1

Step-by-step explanation: