Question

The perimeter of an isosceles triangle is 67/9 cm
cm. If the equal sides measure 13/6 cm
each, find the measure of the remaining side​

Answer 1

Answer:

The remaining side is $\frac{28}{9}$ cm

Step-by-step explanation:

We have been given here that the respective perimeter of the isosceles triangle is $\frac{67}{9}$ cm . As we know that the isosceles triangle has all its sides equal and it has been also mentioned that one of its equal sides is $\frac{13}{6} cm$ . Therefore we assume the third side to be n and we have,

Perimeter = sum of all the sides

∴ $\frac{67}{9} = \frac{13}{6} + \frac{13}{6} + n$

⇒ $\frac{67}{9} = n + 2$ × $\frac{13}{6}$

⇒ $\frac{67}{9} = n + \frac{13}{3}$

⇒ n = $\frac{67}{9} - \frac{13}{3}$

Lcm of 3 and 9 is 9 therefore we have,

⇒ n = $\frac{67}{9} - \frac{39}{9}$

⇒ n = $\frac{67-39}{9}$

⇒ n = $\frac{28}{9}$

Therefore the third remaining side is $\frac{28}{9} cm$