The perimeter of an isosceles triangle is32cm..The ratio of the equal side to its base is 3:2 find the area ofthe triangle
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Answered by
1
Step-by-step explanation:
Let the sides of the triangle be3x,3x and 2x.
therefore acc. to question,
3x+3x+2x=32
8x=32x
x=4
Hence the sides of triangle will be
12cm,12cm and 8cm
Answered by
0
the perimeter of isosceles triangle = 32cm
p of isosceles triangle = 2 * equal side + base
let length of equal side be 3x and base be 2x
then
2 * 3x + 2x = 32 cm
6x + 2x = 32cm
8x = 32 cm
x= 4 cm
length of equal side = 3*4= 12cm
length of base = 2*4=8cm
area of isosceles triangle=b*1/4*√4a2-b2
= 8*1/4√4*144-64
=2√512
=2*22.62
= 45.25cm2
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