Math, asked by srsrs193, 11 months ago

The perimeter of an isosceles triangle is32cm..The ratio of the equal side to its base is 3:2 find the area ofthe triangle

Answers

Answered by shayrakhan
1

Step-by-step explanation:

Let the sides of the triangle be3x,3x and 2x.

therefore acc. to question,

3x+3x+2x=32

8x=32x

x=4

Hence the sides of triangle will be

12cm,12cm and 8cm

Answered by soniabikash
0

the perimeter of isosceles triangle = 32cm

p of isosceles triangle = 2 * equal side + base

let length of equal side be 3x and base be 2x

then

2 * 3x + 2x = 32 cm

6x + 2x = 32cm

8x = 32 cm

x= 4 cm

length of equal side = 3*4= 12cm

length of base = 2*4=8cm

area of isosceles triangle=b*1/4*√4a2-b2

= 8*1/4√4*144-64

=2√512

=2*22.62

= 45.25cm2

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