Question

The perimeter of an isosceles triangle whose one of the equal sides is 12 cm, is 32cm
Find the other two sides of the triangle.​

Answer 1

Answer is 8 cm as

Step-by-step explanation:

Perimeter of Triangle= Sum of its three sides

32cm = 12cm+12cm+ x cm

32cm-24cm= x cm

x= 8 cm

Note: The question has mentioned clearly that the measure of its equal side is 12cm, but if it says ONE OF SIDES IS 12cm then the solution will be as follows:

32cm= 2x cm+12cm (2x as two sides of an isosceles triangle are equal)

2x cm= 20cm

x= 10 cm

Please mark it as BRAINLIEST.

Answer 2

Step-by-step explanation:

GIVEN

Base = 12cm

Perimeter = 32 cm

SOLUTION

Sum of other 2 Sides = 32-12 = 20

Equal sides = 20/2 = 10cm each

Sides of this triangle 12, 10, 10

Semi perimeter = (12+10+10)/2 = 32/2 = l6 cm

Area = √[s (s-a)(s-b)(s-c)]

= √[16 (16-12) (16-10) (16-10)]

= √[16x4x6x6]

= 48 cm²