The perimeter of an isosceles triangles is 42 cm and its base is 1 1/2 t... The perimeter of an isosceles triangles is 42 cm and its base is 1 1/2 times each of the equal of the equal sides. Find (i) the length of each side of the triangle (ii) the area of the triangle, and (iii) hte height of the triangle
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Taking the triangle is ABC where AB and AC are the 2 equal sides and BC the base.
Let BC be 3 units and AB and AC be 2 units each.
Total perimeter: 3+2+2=7 units
length of each equal side = (42/7)×2 = 12 cm
Length of base = (42/7)×3 = 18 cm
height of triangle = sq root ((12^2)-((18/2)^2)) = root63
area of triangle = (1/2)×18×root63 = 9root63 = 71.4352854 = 71.4 (3sf)
Please tell me if I'm wrong.
Let BC be 3 units and AB and AC be 2 units each.
Total perimeter: 3+2+2=7 units
length of each equal side = (42/7)×2 = 12 cm
Length of base = (42/7)×3 = 18 cm
height of triangle = sq root ((12^2)-((18/2)^2)) = root63
area of triangle = (1/2)×18×root63 = 9root63 = 71.4352854 = 71.4 (3sf)
Please tell me if I'm wrong.
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