The perimeter of an isoscles triangle is 32 CM the ratio of the equal side to its base is 3 :2 find the area of The triangle
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The ratio of the equal side to the base is 3:2.
Let the sides be 3x, 2x. Let the third =3x
Given, perimeter =32
We know that the perimeter is equal to the sum of the sides. Thus,
⇒3x+2x+3x=32
⇒8x=32
⇒x=4
Thus, the sides are 12 cm, 8 cm, 12 cm
Thus, Area of the triangle = √(s-a)(s-b)(s- c). s=a +b +c /2
a=12, b=12 and c=8
√(16−12)(16−8)(16-12)
√16×4×8×4
=√4×4×4×4×2×4
=32√2 cm^2 ans
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