The perimeter of angle ABC is 50 cm. It’s sides AB, BC and AC are respectively 15cm, 10cm and (x+4) cm. Find the value of x?
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Answered by
4
AB+BC +AC=50
15+10+(x+4 ) =50
25+x+4=50
29+x=50
x=50-29
x=21
15+10+(x+4 ) =50
25+x+4=50
29+x=50
x=50-29
x=21
Answered by
4
perimeter of an angle = sum of all sides
50cm=15cm+10cm+(X+4)cm
50cm =29+x
50-29=x
21=x
YOURRR ANSWERR ISS HEREE
50cm=15cm+10cm+(X+4)cm
50cm =29+x
50-29=x
21=x
YOURRR ANSWERR ISS HEREE
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