Question

the perimeter of arectangle is 270 m. if its breadth is 30m, find it's length and area?​

Answer 1

Answer:

$length = 105m \\ area = 3150 {m}^{2}$

Step-by-step explanation:

$breadth \: of \: rectangle \: = 30m \\ perimeter = 270m \\ 2(l + b) = 270m \\ 2(l + 30m) = 270m \\ 2l + 60m = 270m \\ 2l = 270m - 60m \\ 2l = 210m \\ l = \frac{210m}{2} \\ l = 105m \\ length = 105m \\ \\ area = l \times b \\ = 105m \times 30m \\ = 3150 {m}^{2}$