Question

the perimeter of arectangle is 52 cm where length is 6 more than the width of the rectangle form the pair of linear equation for the above situation and find the dimension of the rectangle graphically​

Answer 1

let width be x

A/Q

length=x+6

now,

perimeter of rectangle = 2(l*b)

52 = 2( x+6*x)

52 = 2x+12+2x

52-12= 4x

40/4 = x

10 = x

Thus,

width = x = 10 CM

length = x+6 =10+6=16cm