The perimeter of certain sector of a cirlce of radius 6.5 cm is 31 cm. Find the area of sector
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perimeter of sector=l+2r
let us find the value of "l"
l+2(6.5)=31
l+13=31
l=31-13
since,l=18
area of sector=lr/2
18(6.5)/2
9(6.5)
58.5
Therefore, area of Sector=58.5
let us find the value of "l"
l+2(6.5)=31
l+13=31
l=31-13
since,l=18
area of sector=lr/2
18(6.5)/2
9(6.5)
58.5
Therefore, area of Sector=58.5
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