The perimeter of equilateral triangle is 18cm then hight of e
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√[(6)²-(3)²]=√[36-9]=√27=3√3cm
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HEYA !
Let ∆ABC is that equilateral triangle
[ See above Figure ]
Given that,
Perimeter of triangle is 18 cm
Perimeter = 18 cm
3 × Side = 18 cm
→ Side = 6 cm
→ AB = BC = AC = 6 cm
Now ,
An altitude AD is drawn from A
[ This is height of ∆ABC ]
Then,
BD = DC = 3 cm
Now,
Using Pythagoras theorem in ∆ACD ,
We have
AC² = AD² + DC²
6² = AD² + 3²
36 = AD² + 9
→ AD² = 36 - 9
→ AD = √27
→ AD = 3√3 cm
Hence,
The height is 3√3 cm
Let ∆ABC is that equilateral triangle
[ See above Figure ]
Given that,
Perimeter of triangle is 18 cm
Perimeter = 18 cm
3 × Side = 18 cm
→ Side = 6 cm
→ AB = BC = AC = 6 cm
Now ,
An altitude AD is drawn from A
[ This is height of ∆ABC ]
Then,
BD = DC = 3 cm
Now,
Using Pythagoras theorem in ∆ACD ,
We have
AC² = AD² + DC²
6² = AD² + 3²
36 = AD² + 9
→ AD² = 36 - 9
→ AD = √27
→ AD = 3√3 cm
Hence,
The height is 3√3 cm
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