the perimeter of floor of a rectangular hall is 215 the cost of the whitewashing its4 was 10 rupees 15000 of the rate of rupees 10 rupees per metre find the height of the room
Answers
Answer:
Find the smallest number which when divided by 18, 12, and 24 leaves a remainder of 16, 10, and 22 respectively.Find the smallest number which when divided by 18, 12, and 24 leaves a remainder of 16, 10, and 22 respectively.Find the smallest number which when divided by 18, 12, and 24 leaves a remainder of 16, 10, and 22 respectively.
Answer:
6m
Step-by-step explanation:
The height of the hall is 6 m.
Step-by-step explanation:
Perimeter of the floor of hall = 250 m.
Cost of painting the four walls = Rs.15,000
Let the dimension of rectangular hall be m.
Area of four walls is given by,
....(1)
Perimeter of the floor of hall is given by,
We have given P=250 m
....(2)
Substitute (2) in (1),
Cost of painting per m² area = Rs.10
Cost of painting area =
Cost of painting area = Rs.2500h
The cost of painting the walls is Rs.15000 .
i.e.
Therefore, the height of the hall is 6 m.
#Learn more
"Question 3 The floor of a rectangular hall has a perimeter 250 m. If the cost of panting the four walls at the rate of Rs.10 per m^2 is Rs.15000, find the height of the hall. [Hint: Area of the four walls = Lateral surface area.]