Math, asked by mdfaisal4395gmailcom, 1 month ago

The perimeter of floor of a rectangular hall is 250m. Find the cost of whitewashing the four walls of height 8m at the rate of 7.50 per m2.
A.₹19350
B.₹15000
C.₹ 14000
D.₹ 15500
Ans=B:Rs15000
Steps-
(Given)Base perimeter=250m(perimeter of floor)
Total coast= Lateral Surface Area(LSA)×7.50
Lsa= Base perimeter×h
=250×8=>2000m2
Total cost=2000×7.50=>Rs15000.

Answers

Answered by rathinaporkodig
0

Answer:

Perimeter of the floor of hall = 250 m.

Cost of painting the four walls = Rs.15,000

Let the dimension of rectangular hall be  m.

Area of four walls is given by,

....(1)

Perimeter of the floor of hall is given by,

We have given P=250 m

 ....(2)

Substitute (2) in (1),

Cost of painting per m² area = Rs.10

Cost of painting   area =                                   Cost of painting   area =  Rs.2500h

The cost of painting the walls is Rs.15000 .

i.e.  

Step-by-step explanation:

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