The perimeter of floor of rectangular hall is 250m. The cost of white washing the
four walls @ 100/- is 15000/- Find the height of the hall
Answers
The height of the hall is 6 m.
Step-by-step explanation:
Perimeter of the floor of hall = 250 m.
Cost of painting the four walls = Rs.15,000
Let the dimension of rectangular hall be l\times b\times hl×b×h m.
Area of four walls is given by,
A= 2lh + 2bhAA=2lh+2bhA
A=2(l + b) hA=2(l+b)h ....(1)
Perimeter of the floor of hall is given by,
P= 2(l + b)P=2(l+b)
We have given P=250 m
250= 2(l + b)250=2(l+b) ....(2)
Substitute (2) in (1),
A=250\times hA=250×h
A=250h\ m^2A=250h m
2
Cost of painting per m² area = Rs.10
Cost of painting 250h\ m^2250h m
2
area = Rs.250h\times 10Rs.250h×10
Cost of painting 250h\ m^2250h m
2
area = Rs.2500h
The cost of painting the walls is Rs.15000 .
i.e. 2500h=150002500h=15000
h=\frac{15000}{2500}h=
2500
15000
h=6h=6
Answer:
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Step-by-step explanation:
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