Question

The perimeter of floor of room is 40 m and height is 4m.
find area of four walls of room​

Answer 1

perimeter = 40m.

length=?

breadth =4m.

Step-by-step explanation:

perimeter=2(l+b)

40=2(l+4)

40/2=(l+4)

20=(l+4)

20l+80

l=80/20

l=4

area= l×b

4×4

16m^2

Answer 2

Given:-

• Perimeter of the floor of a room is 40 m.
• Height of the floor of a room is 4 m.

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To find:-

• Area of the four walls of a room.

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Solution:-

Here,

• Perimeter = 40 m
• Height (h) = 4 m

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According to the question

⇛ 2(l + b) = 40 ⠀⠀⠀⠀ ....(i)

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★Formula used:-

Lateral surface area = 2(l + b)h

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⇛ 2(l + b)h

⇛ 40 × 4 ⠀⠀⠀⠀⠀....(i)

⇛ 160 m²

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Hence,

• the area of four walls of a room is 160 m².

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⛦More Formulas:-

→ Area of rectangle = length × breadth sq.units

→ Perimeter of square = 4 × side units

→ Area of square = side × side sq.units

→ Perimeter of circle = 2πr units

→ Area of circle = πr² sq.units

→ Perimeter of parallelogram = 2 × (a + b) units

→ Area of parallelogram = base × height sq.units

→ Perimeter of rhombus = 4 × side units

→ Area of rhombus = 1/2 × diagonal (1) × diagonal (2) sq.units

→ Perimeter of equilateral triangle = 3 × side units

→ Area of equilateral triangle = √3/4 × a² = 1/2 × side × height sq.units

→ Perimeter of trapezoid = (Sum of all sides) units

→ Area of trapezoid = 1/2 × height × (sum of parallel sides) sq.units