Question

The perimeter of ∆ is 50 cm. It’s sides are AB =15 cm , BC=10 cm and AC= (x+4) cm. Find the value of x.​

Answer 1

Answer:

The answer is x= 11 if the triangle is isoceles triangle

Answer 2

Answer:

The value of $x$ is 21cm.

Explanation:

Given sides of the triangle :

• 15cm, 10cm, and $(x + 4)$cm

Perimeter :

• 50cm.

Find the value of $\boldsymbol x$ :

We know that,

Perimeter of a triangle : Sum of all sides

Or,

$\to 15 + 10 + (x + 4)$

But, the perimeter is 50 (given)

So, we can say that

$\implies 15 + 10 + (x + 4) = 50$

Solving for $\boldsymbol x$ :

$\implies 15 + 10 + x + 4 = 50$

$\implies 29 + x = 50$

$\implies x = 50 - 29$

$\implies x = 21$

${ \therefore{ \sf{The \: value \: of \boldsymbol{x} \: is \: 21}}}$