the perimeter of isosceles triangle is 14cm and the ratio of lateral side to base is 5:4. find area of triangle
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Answered by
1
5x+5x+4x=14
14x=14
x=1
the sides of triangle are 5,5,4
area=√p(p-a)(p-b)(p-c)
=√7(7-5)(7-5)(7-4)
=√12×7
=√84
=9.17
14x=14
x=1
the sides of triangle are 5,5,4
area=√p(p-a)(p-b)(p-c)
=√7(7-5)(7-5)(7-4)
=√12×7
=√84
=9.17
Answered by
0
let the side of triangle be 5x,5x ,4x the
give that perimeter is 14
this employs
5x+5x+4x=14
14x=14
x=14/14
x=1
area=√p(p-a)(p-b)(p-c)
=√7(7-5)(7-5)(7-4)
=√12×7
=√84
=9.17
give that perimeter is 14
this employs
5x+5x+4x=14
14x=14
x=14/14
x=1
area=√p(p-a)(p-b)(p-c)
=√7(7-5)(7-5)(7-4)
=√12×7
=√84
=9.17
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