Question

The perimeter of isosceles triangle is 32 cm the ratio of the equal side of its base is 302 find the area of the triangle

Answer 1

Ratio can't be 302 it may be 3:2. with that 3:2 I am doing this math

Since two sides of isolated triangles are equal

Side A = 3x

Side B = 3x

Side C = 2x

Perimeter = 3x + 3x + 2x = 32

8x = 32

x = 4

A = 12 cm

B = 12 cm

C = 8 cm

S = 32/2 = 16

Area = √(16 (16 - 12) (16 -12) (16 - 8)]

√16 x 4 x 4 x 8

32√2 cm²

Answer 2

Answer:

32 root 2

Step-by-step explanation:

The perimeter of an isosceles triangle is 32 cm. The ratio of the equal side to its base is 3 : 2. Find the area of the triangle.

The perimeter of isosceles Triangle=32cm

The ratio of the equal sides of its base is 3:2

The ratio of equal sides and base be X

The length of equal sides be 3x

The length of base be 2x

Now sides of Triangle are

Find semi perimeter here

a=12 b=12 c=8

Using heron's formula here

Hence,

The area of isosceles Triangle=32√2cm²

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