Question

the perimeter of parallallagram is 300m. one of sides is 50m more than its adjacent side. find the length of sides of the paralleogram​

Answer 1

☆ Solution ☆

Given :-

• The perimeter of parallallagram is 300 m.
• One of sides is 50 m more than its adjacent side.

To Find :-

• The length of sides of the paralleogram.

Step-by-Step-Explaination :-

Let one side be x

And second side be x + 50 m

As we know that :-

Perimeter of rectangle = 2 ( l + b )

Putting the respective value,

2 ( x + x + 50 ) = 300

2 ( 2x + 50 ) = 300

4x + 100 = 300

4x = 300 - 100

4x = 200

x = 200/4

x = 50

So,

One side = 50

Second side = x + 50 = 100

Hence Solved!

Answer 2

$\bf {\underline {\underline{✤QƲЄƧƬƖƠƝ}}}$

The perimeter of parallallagram is 300m. one of sides is 50m more than its adjacent side. find the length of sides of the paralleogram.

$\bf {\underline {\underline{✤ ƛƝƧƜЄƦ}}}$

Length of sides of parallelogram are 50m and 100m

$\bf {\underline {\underline{✤ ƓƖƔЄƝ}}}$

• One of sides is 50m more than its adjacent side
• Perimeter of parallallagram is 300m

$\bf {\underline {\underline{✤ ƬƠ \: \: ƇƛLƇƲLƛƬЄ}}}$

• Length of sides of parallelogram

$\bf {\underline {\underline{✤ ƑƠƦMƲLƛ \: \: ƬƠ \: ƁЄ \: \: ƲƧЄƊ}}}$

Perimeter of parallallagram

$\bf \pink{2(l + b)}$

$\bf {\underline {\underline{✤ SƠԼƲƬƖƠƝ}}}$

Let one side be x

then, other side be x + 50

$\bf \: perimeter = 2(l + b)$

$\bf \implies 300 = 2(x + x + 50)$

$\bf \implies 300 = 2(2x + 50)$

$\bf \implies 300 = 4x + 100$

$\bf \implies 4x + 100 = 300$

$\bf \implies 4x = 300 - 100$

$\bf \implies 4x = 200$

$\bf \implies x = 200 \div 4$

$\bf \implies \: x = 50m$

$\bf \blue{length \: of \: sides \ratio - }$

• x = 50m
• x + 50 = 50 + 50 = 100m

Therefore, sides of parallelogram are 50m and 100m.