Question

The perimeter of parellogram
is 150 im One
of its sides is greater than the other by 33cm
find the lengths of the sides of the parellogram.​

Answer 1

Answer:

Let, the smaller side of the parallelogram be 'x'

then the greater side of the parallelogram will be 'x+33'.

Now the perimeter of a parallelogram is,

P = 2 [ greater side + smaller side]

150 = 2 [ ( x + 33 ) + x ]

150 = 2 [ x + x + 33 ]

150 = 2 [ 2x + 33 ]

Dividing by 2 to both sides we get ,

75 = 2x + 33

2x = 75 - 33

2x = 42

x = 42÷2

x = 21 cm ......

x + 33 = 21 + 33 = 54 cm...

Therefore,the side of the smaller and greater sides of the parallelogram are 21 cm and 54 cm respectively.

Mark brainliest!

Step-by-step explanation:

Answer 2

Answer:

54 ｃｍ

Step-by-step explanation:

$\blue{ \bold{ \underline{ \bf{QUESTION : - }}}}$

The perimeter of a parallelogram is 150 cm and one of its side is greater than the other by 33 cm. Find the lengths of all the sides of that parallelogram

_____________________________

$\boxed{ \huge{ \bold{Given}}}$

• Perimeter of Parallelogram = 150 cm

• Length is 33 Greater than breadth

$\boxed{ \huge{ \bold{to \: find}}}$

• Length of the Parallelogram

$\star{ \pink{ \underline{ \underline{Ｓｏｌｕｔｉｏｎ : - }}}}$

$\boxed{ \underline{ \red{ \sf{LeT, }}}}$

• Breadth = b

Than,

• Length = b + 33

We Know :-

$\boxed{ \boxed{ \orange{ \sf{Perimeter \: of \: Parallelogram = 2 \: (l + b)}}}}$

$\implies{ \sf{ \large{ \bold{150 = 2 \: (b + 33 + b)}}}}$

$\implies{ \sf{ \large{ \bold{150 = 2(2b + 33)}}}}$

$\implies{ \sf{ \large{150 = 4b + 66}}}$

$\implies{ \sf{ \large{150 - 66 = 4b}}}$

$\implies{ \sf{ \large{84 = 4b}}}$

$\implies{ \sf{ \large{ \frac{84}{4} = b}}}$

$\implies{ \sf{ \large{ \cancel\frac{84}{4} = b}}}$

$\purple{ \boxed{ \sf{ \frak{ {21 \: cm = b}}}}}$

We find Breadth = 21 cm,

We find Breadth = 21, We know, Length is 33 greater than Breadth

$\therefore \sf{ \sf{ \green{puting \: breadth \: value \: in \: lenght}}}$

$\boxed{ \gray{Length = b + 33}}$

$\implies{ \sf{ \large{ lenght = 21 + 33}}}$

$\boxed{\sf{ \large{ \red{ \frak{lenght = 54 \: cm}}}}}$

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