Question

The perimeter of pool is 104 m the length is 1m more than twice the width find the length and width

Answer 1

Answer:

Given :

Perimeter = 104 m

Let the Width of pool = X

Let the length of pool = 1 m +2x

(because length is 1 m more then twice of width)

so, the perimeter = 2(length + breath)

2(x +1+2x) = 104

= 2(3x +1) = 104

= 6x +2 = 104

= 6x = 104-2

= 6x = 102

= X = 102/6

= X = 17

Hence the width = X = 17 m

and length = 1 m +2x

= 1 m +2(17)

= 1 m +34

length = 35 m

so, Length = 35 m

Width = 17 m

VERIFICATION

Perimeter = 2 (length + breadth)

2 (17 + 35) = 104

2 (52) = 104

104 = 104

LHS = RHS

Hence proved.

Answer 2

✬ Length = 35 m ✬

✬ Width = 17 m ✬

Step-by-step explanation:

Given:

• Perimeter of a pool is 104 m.
• Length of pool is 1 m more than twice the width.

To Find:

• What is the measure of length & width of pool ?

Solution: Let the measure of width of pool be x m. Therefore

➟ Length of pool = (Twice the width + 1) m

➟ Length = (2x + 1) m

Since, the pool is in rectangular form. So

★ Perimeter of Rectangle = 2 ( Length + Width )★

A/q

• Perimeter of pool = 104 m

$\implies{\rm }$ 104 = 2 ( Length + Width )

$\implies{\rm }$ 104 = 2 ( 2x + 1 + x )

$\implies{\rm }$ 104 = 2 $\times$ ( 3x + 1 )

$\implies{\rm }$ 104 = 6x + 2

$\implies{\rm }$ 104 – 2 = 6x

$\implies{\rm }$ 102 = 6x

$\implies{\rm }$ 17 m = x

So,

➙ Length of pool = (2x + 1) m

➙ Length = 2(17) + 1 = 34 + 1 = 35 m

➙ Width of pool = x = 17 m

______________________

★ Verification ★

➳ 104 = 2 ( Length + Width )

➳ 104 = 2 ( 35 + 17 )

➳ 104 = 2 $\times$ 52

➳ 104 = 104

[ Verified ]