Question

the perimeter of quadrant of a circle whose radius is 7/2 cm is​

Answer 1

$\huge\green{\boxed{\sf Answer}}$

Perimeter of quadrant = Length of arc + 2 × radius

Perimeter of quadrant = (1/4 x 2 x 22/7 x 7/2) + 2 x 7/2

Perimeter of quadrant = 11/2 + 7

Perimeter of quadrant

= 11 + 14 / 2

= 25/2

= 12.5 cm

Answer 2

Hint:

The perimeter of a quadrant of a circle whose radius is $r$, is given by

$\quad \dfrac{1}{4}(2\pi r)+2r$

Step-by-step explanation:

Given that, the radius of the circle is $\dfrac{7}{2}$ cm

Then the perimeter of a quadrant of the circle

$=\dfrac{1}{4}(2\times \dfrac{22}{7}\times \dfrac{7}{2})+(2\times\dfrac{7}{2})$ cm

• since $\pi=\dfrac{22}{7},r=\dfrac{7}{2}$ cm

$=\dfrac{1}{4}(22)+7$ cm

$=\dfrac{11}{2}+7$ cm

$=\dfrac{11+14}{2}$ cm

$=\dfrac{25}{2}$ cm

$=12.5$ cm

Final answer: 12.5 cm

The perimeter of a quadrant of the circle whose radius is $\dfrac{7}{2}$ cm, is $12.5$ cm.

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