Question

the perimeter of reclangular, Park is 40m and
the length of the park is 12cm Find its 28m breadth
​

Answer 1

Step-by-step explanation:

Area of lawn ABCD = 40 m x 25 m = 1000 m2

Length PQ = (40 + 2 + 2 ) m = 44 m

Breadth QR = ( 25 + 2 + 2 ) m = 29 m

∴ Area of PQRS = 44 m x 29 m = 1276 m2

Now,

Area of the path = Area of PQRS − Area of the lawn ABCD

= 1276 m2 − 1000 m2

= 276 m2

Rate of levelling the path = Rs. 8.25 per m2

∴ Cost of levelling the path = Rs. ( 8.25 x 276)

= Rs. 2277