Question

the perimeter of rectangle 13 cm and its width is 23/4 CM find ite lengtn
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Answer 1

Answer:

tooo easy ¾ answer

Step-by-step explanation:

• 2 x (23/4 + x ) = 13
• 23/2 + 2x = 13
• 23/2 = 11.5
• 2x = 13 - 11.5 = 1.5
• x = 1.5 /2= 15/10 x 1/2 = 15 / 20 = 3 / 4
• lenght = ¾

Answer 2

Given :

• Perimeter of Rectangle is 13 cm.
• Width of Rectangle is 23/4 cm.

To Find :

• Length of Rectangle .

Solution :

$\longmapsto\tt{Width=\dfrac{23}{4}\:cm}$

Using Fomula :

$\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+w)}$

Putting Values :

$\longmapsto\tt{13=2\times{\bigg(l+\dfrac{23}{4}\bigg)}}$

$\longmapsto\tt{\dfrac{13}{2}=l+\dfrac{23}{4}}$

$\longmapsto\tt{\dfrac{13}{2}-\dfrac{23}{4}=l}$

$\longmapsto\tt{\dfrac{26-23}{4}=l}$

$\longmapsto\tt\bf{\dfrac{3}{4}=l}$

So , The Length of Rectangle is 3/4 cm...

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VERIFICATION :

$\longmapsto\tt{13=2\times{\bigg(\dfrac{3}{4}+\dfrac{23}{4}\bigg)}}$

$\longmapsto\tt{13={\cancel{2}}\times{\dfrac{26}{{\cancel{4}}}}}$

$\longmapsto\tt{13=\cancel\dfrac{26}{2}}$

$\longmapsto\tt\bf{13=13}$

HENCE VERIFIED