Question

the perimeter of rectangle is 13 cm and its width is 2 3/4 cm find its length​

Answer 1

Answer:

$length = \frac{perimeter}{2} - breadth$

$\: \: \: \: \: = \frac{13}{2} - \frac{11}{4} \\ \: \: \: \: \: = \frac{26 - 11}{4} \\ \: \: \: \: \: = \frac{15}{4} \\ \: \: \: \: \: = 3 \frac{3}{4}$

Answer 2

$\huge\underline\mathrm{SOLUTION:-}$

AnswEr:

• Length of the rectangle = 15/4 Cm.

Given:

• The perimeter of rectangle is 13 Cm.
• Width of the rectangle is $\mathsf {2\frac{3}{4}\:Cm}$

Need To Find:

• Length of the rectangle = ?

ExPlanation:

Let 'L' and 'B' be the length and width of the triangle respectively.

• B = $\mathsf {2\frac{3}{4}\:Cm }$ [Given] = $\mathsf {\frac{11}{4} }$
• And Perimeter of the rectangle = 13 Cm [Given]

2(L + B) = 13

➠ 2L + 2B = 13

➠ 2L + 2(11/4) = 13

➠ 2L + 11/2 = 13

➠ 2L = 13 - 11/2

➠ 2L = 26 - 11/2

➠ L = 15/4 Cm

ThereFore:

• Length of the rectangle is 15/4 Cm.

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$