Question

the perimeter of rectangle is 13 cm and its width is 2³/4 cm fi d it's length
hello guys please answer me this one
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Answer 1

The perimeter of a rectangle is 13 cm and its breadth is 2 3/4cm

let lenght be l

now 2 \frac{3}{4}2

4

3

=> 11/4 cm

perimeter of rectangle = 2(l+b)

so ,

13 = 2(l+b)

13 = 2(l+11/4)

13 = 2l +11/2

13 - 11/2 = 2l

26-11/2 = 2l

15/2 = 2l

=>l= 15/2*2

=>l = 15/4cm

hope it help

Answer 2

Given

We have given perimeter of Rectangle is 13cm

breadth of Rectangle is 2¾ cm.

To Find

We have to find the length of the Rectangle

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

How to solve :

Step1:Firstly write down the formula for Perimeter of Rectangle.

Step2:length is not given so,assume some Variable to complete the formula.

Step3: Evaluate it and hence we will find the length.

Perimeter of Rectangle= 2(length+ breadth)

=>13= 2(. length +11/4)

let the length of the Rectangle be 'x'cm

=>13= 2( x+11/4)

=> 13= 2(4x+11/4)

=>13/2= 4x+11/4

=>13= 4x+11/2

=>26= 4x+11

=>26-11=4x

=>15=4x

=>x= 15/4=3.75cm

hence,length is 3.75cm & breadth is 11/4 (2.75) cm

Check:

Perimeter of Rectangle= 2(3.75+2.75)

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$=2(6.5)

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$=13

Extra information=>

Perimeter is the total distance occupy by a solid 2D figure around its edge.

some Properties of Rectangle

• A rectangle is a type of quadrilateral.
• Opposite sides are parallel & equal
• Sum of all Interior angles makes 360°
• Diagonals bisects each other and both diagonals are of same length.