Question

the perimeter of rectangle is 210m and its length is 15m more than double the width find its length and width​

Answer 1

Answer:

Width of rectangle is 30 m

Length of rectangle is 75 m

Step-by-step explanation:

Let,

Width of rectangle (b) = x

Length of rectangle (l) = 2x + 15

The perimeter of rectangle = 210 m

The perimeter of rectangle = 2 (length + width)

⇒ 2 (2x + 15 + x) = 210

⇒ 2 (3x + 15) = 210

⇒ 6x + 30 = 210

⇒ 6x = 210 - 30

⇒ 6x = 180

⇒ x = 180 / 6

⇒ x = 30

Hence,

Width of rectangle (b) = 30 m

Length of rectangle (l) = 2x + 15

⇒ 2x + 15

⇒ 2 (30) + 15

⇒ 60 + 15

⇒ 75

Therefore,

Width of rectangle is 30 m

Length of rectangle is 75 m

Answer 2

Perimeter of rectangle = 210 m

Width (b) = x m

Length (l) = (2x + 15) m

Formula for perimeter of rectangle=2(l+b)

Perimeter of rectangle = 2(2x+15+x) m

210 = 2(3x+15)

➟ 105 = 3x+15

➟ 105-15 = 3x

➟ 90 = 3x

➟ x = 90/3

➟ x = 30

Width = x m = 30 m

Length = (2x + 15) m = 60+15 = 75 m