Question

The perimeter of rectangle is 26 cm and its width is 11/2 cm , its length is​

Answer 1

Answer:

Given,

perimeter of rectangle = 26 cm

width of rectangle = 11/2 cm

let length be x .

perimeter of rectangle = 2( l + b )

26 = 2 ( x + 11/2 )

26 = 2 x + 22/2

26 = 2 x + 11

26 - 11 = 2 x

15 = 2 x

15/2 = x

So , length of rectangle is 15/2 cm.

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Answer 2

Answer:

Perimeter 26cm

Width =11/2cm

Let the length be x.

ATQ

$2( \frac{11}{2} + x) = 26 \\ ( \frac{11 + 2x}{2} ) = \frac{26}{2} \\ 11 + 2x = \frac{26}{2} \times 2 \\ 2x = 26 - 11 \: \: \: \: \: \: \: \: \: \\ x = \frac{15}{2} =7 \frac{1}{2} \: \: \: \: \: \: \: \: \:$

Therefore, length =x=7 whole 1/2cm

Step-by-step explanation:

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