Question

the perimeter of rectangle is 280 m if the radius is 26 less than the length find the length and width​

Answer 1

Solution:

Dimensions of the rectangle:

Let width = w m

length = (w+26)m

i ) Perimeter = 280 m[given]

=>2[length+width] = 280

=> 2[w+26+w] = 280

=> 2w+26 = 280/2

=> 2w+26 = 140

=> 2w = 140 - 26

=> 2w = 114

=> w = 114/2

=> w = 57 m

Therefore,

width (w) = 57m

length = w+26

= 57+26

= 83 m

••••

Answer 2

Given :

• Perimeter of the rectangle = 280 m.
• The width is 26 less than the length of the rectangle.

To find :

• Dimensions of the rectangle =?

Formula Used :

• Perimeter of the rectangle = 2(length + breadth)

Step-by-step explanation :

It is Given that,

Perimeter of the rectangle = 280 m.

The width is 26 less than the length of the rectangle.

Now,

Let, the breadth of the rectangle be, x.

Then, the length of the rectangle be, x + 26.

As We know that,

Perimeter of the rectangle = 2(length + breadth)

Substituting the values in the above formula, we get,

280 = 2 (x + x + 26)

280 = 2(2x + 26)

280 = 4x - 52

4x = 280 - 52

4x = 228

x = 228/4

x = 57.

Hence,

The breadth of the rectangle, x = 57 m

Then, the length of the rectangle, x + 26 = 57 + 26 = 83 m