the perimeter of rectangle is 28m and it's area is 48m² what is its length of diagnol
Anonymous:
as we know that the perimeter of rectangle = 2(l +b ) then from this l+ b = 14 and also area of rectangle = l ×b = 48 therefore by equating l = 8 and b = 6 then as diagonal divides it into two right angle triangle then by applying Pythagorean theorem diagonal = HYPOTENUSE = 10 cm
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yes rohit is correct
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