Question

the perimeter of rectangle is 28x cube+8x sqare+4.one of its sides is 8x square +4x. find the other side. ​

Answer 1

Correct Question :–

The perimeter of rectangle is 28x³ + 16x² + 8x + 4. One of its sides is 8x² + 4x. Find the other side.

Given :–

• Perimeter of a rectangle = 28x³ + 16x² + 8x + 4.
• One side of a rectangle = 8x² + 4x.

To Find :–

• The other side of a rectangle.

Solution :–

We know that,

Perimeter of a rectangle = 28x³ + 16x² + 8x + 4

↣ 2l + 2b = 28x³ + 16x² + 8x + 4

Now, put the given values.

↣ 2(8x² + 4x) + 2b = 28x³ + 16x² + 8x + 4

Open the bracket.

↣ 16x² + 8x + 2b = 28x³ + 16x² + 8x + 4

↣ 2b = (28x³ + 16x² + 8x + 4) – (16x² + 8x)

Again, open both the brackets.

↣ 2b = 28x³ + 16x² + 8x + 4 – 16x² – 8x

↣ 2b = 28x³ + 16x² – 16x² + 8x – 8x + 4

↣ 2b = 28x³ + 0 + 0 + 4

↣ 2b = 28x³ + 4

↣ b = $\sf \dfrac{{28x}^{3} + 4}{2}$

Now, divide the denominator (2) and numerator numbers (28 and 4), we obtain

↣ b = 14x³ + 2

Hence,

The other side of a rectangle is 14x³ + 2.

Check :–

Perimeter of a rectangle = 28x³ + 16x² + 8x + 4

↣ 2l + 2b = 28x³ + 16x² + 8x + 4

↣ 2(14x³ + 2) + 2(8x² + 4x) = 28x³ + 16x² + 8x + 4

Now, open both the brackets.

↣ 28x³ + 4 + 16x² + 8x = 28x³ + 16x² + 8x + 4

↣ 28x³ + 16x² + 8x + 4 = 28x³ + 16x² + 8x + 4

Since, the L.H.S. and the R.H.S. are equal.

So, the other side is 14x³ + 2 is correct.