The perimeter of rectangle is 30 if its length exceeds it's breadth by 3 meter find its length
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Perimeter=2 [ l(lenght) +b(breadth) ]
30 = 2 (l+b)
30/2= l+b
l+b=15
now it is given that length exceeds the breadth
so, b= l + 3
putting this value of 'b' in the first equation,
l + (l+3)= 15
l + l + 3=15
2l + 3 = 15. (here it is not twenty one..it is two l)
2l= 15-3
2l= 12
l= 12/2
l=6 metre
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